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  • A cylindrical conductor has uniform cross section. Resistivity of its material Increases linearly from left end to right end. If a constant current is flowing through it and at a section of distanc

A cylindrical conductor has uniform cross section. Resistivity of its material Increases linearly from left end to right end. If a constant current is flowing through it and at a section of distance x from left end, magnitude of electric field intensity is E, which of the following graphs is correct?

Option: 1


Option: 2


Option: 3


Option: 4


Answers (1)

best_answer

If you take resistivity at a distance ‘x’ from left end as\mathrm{\rho=\left(\rho_0+\alpha x\right)}, then electric field intensity at this point will be \mathrm{E=\frac{i P}{A}} where i is the current flowing through the conductor.

Therefore\mathrm{E \propto P \text { and } E(x)=\frac{i}{A}\left(\rho_0+\alpha x\right)}

Hence choice (2).

Posted by

Deependra Verma

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