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  • A dc source of emf  and internal resistance <img alt="r=0.5\Omega" src="https://ent

A dc source of emf E_{1}=100 V and internal resistance r=0.5\Omega, a storage battery of emf E_{2}=90V and an external resistance R are connected as shown in figure. For what value of R no current will pass through the battery ?

Option: 1

5.5\Omega


Option: 2

3.5\Omega


Option: 3

4.5\Omega


Option: 4

2.5\Omega


Answers (1)

best_answer

Given E  = 100V, r = 0.5ohms, e = 90V.

For no current to flow through the battery,

E/V = (R+r)/R

100/90 = (R+0.5)/R

Hence R = 4.5 ohms

Posted by

Sanket Gandhi

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