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A director circle is drawn to the circle \mathrm{x^2+y^2=4}. Then a director circle is drawn to this director circle. If this process is performed \mathrm{n} number of times, so that the equation of last of these circles is \mathrm{x^2+y^2=64}. Then \mathrm{n} is equal to
 

Option: 1

7


Option: 2

8


Option: 3

5


Option: 4

4


Answers (1)

best_answer

The radius of the \mathrm{n^{th}} circle \mathrm{=4.2^n=64}

\mathrm{ \Rightarrow \mathrm{n}=4 \text {. }}

Hence option 4 is correct.
 

Posted by

manish

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