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  • A fair dice is tossed two times. The probability that the second toss results in a value that is higher than the first loss is  Option: 1 <p

A fair dice is tossed two times. The probability that the second toss results in a value that is higher than the first loss is
 

Option: 1

\frac{2}{36}
 


Option: 2

\frac{2}{6}
 


Option: 3

\frac{5}{12}
 


Option: 4

\frac{1}{2}


Answers (1)

best_answer

Total cases =36
In the first toss results can be 1, 2, 3, 4, 5 .
for 1 , the second toss result can be 2, 3, 4, 5, 6, lie., 5 favourable cases
for 2, the second toss result can be 3,4,5,6, i.e., 4 favourable cases
for 3 , the second toss result can be 4,5,6, i.e., 3 favourable cases
for 4 , the second toss result can be 5,6 , i.e., 2 favourable cases
for 5 , the second toss result can be 6 , i.e., 1 favourable cases

\therefore Total favourable cases =15

\therefore Required Probability

=\frac{15}{36}=\frac{5}{12}

Hence option 3 is correct.

Posted by

Ritika Jonwal

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