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A force of 20 \mathrm{~N} is applied at one end of a wire of length 2 \mathrm{~m} and having area of cross-section 10^{-3} \mathrm{~m}^2. The other end of the wire is rigidly fixed. Its coefficient of linear experssion of the wire is \alpha=8 \times 10^{-7} /{ }^{\circ} \mathrm{C} and young's modulus Y=2.2 \times 10^9 \mathrm{~N} / \mathrm{m}^2 and its temperature is increased by 5^{\circ} \mathrm{C}, then the increase in the tension of the wire will be -

Option: 1

4.2\ N


Option: 2

4.4\ N


Option: 3

2.4\ N


Option: 4

8.8\ N


Answers (1)

best_answer

Increase in tension of wire ,

\begin{aligned} &=\ { YA } \alpha . d_\theta \\ & =2.2 \times 10^{11} \times 10^{-2} \times 8 \times 10^{-6} \times 5 \\ & =8.8 \mathrm{~N} \end{aligned}

Posted by

Rakesh

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