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\mathrm{72\Omega} galvanomter is shunted by resistance of \mathrm{8\Omega} . The percentage of the total current which passes through the galvanometer is :

Option: 1

\mathrm{0.1%}


Option: 2

\mathrm{10%}


Option: 3

\mathrm{25%}


Option: 4

\mathrm{0.25%}


Answers (1)

best_answer

\mathrm{i_{2}=\frac{i \times 8}{72+8}=\frac{i}{10}}

Percentage of current passing through galvanometer is

         \mathrm{=\frac{\left(\frac{i}{10}\right)}{i} \times 100=10 \%}

Hence the correct answer is option 2.

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Pankaj

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