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A gas in a piston undergoes a process in which it releases 400 \mathrm{~J} of heat and does 300 \mathrm{~J} of work on its surroundings. Calculate the change in internal energy for this process.

Option: 1

100 J


Option: 2

400 J


Option: 3

700 J


Option: 4

-100 J


Answers (1)

best_answer

According to the first law of thermodynamics,

                  \mathrm{\Delta U=Q+W.}
where \mathrm{\Delta U} is the change in internal energy,

Q is the heat transfer, and W is the work done on the system. But here work is done by the system so, W=-300 \mathrm{~J}
Substituting the values:

\mathrm{ \begin{aligned} & Q=400 \mathrm{~J}, \\ & W=300 \mathrm{~J} . \end{aligned} }

Therefore,

\mathrm{ \Delta U=Q+W=400 \mathrm{~J}-300 \mathrm{~J}=100 \mathrm{~J} }

Posted by

jitender.kumar

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