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  • A gas is subjected to a process during which it absorbs 1200 J of heat and performs 900 J of work on the surroundings. If the initial internal energy of the gas is 2500 J, calculate its final inter

A gas is subjected to a process during which it absorbs 1200 J of heat and performs 900 J of work on the surroundings. If the initial internal energy of the gas is 2500 J, calculate its final internal energy.

Option: 1

600 J


Option: 2

970 J


Option: 3

580 J


Option: 4

2800 J


Answers (1)

best_answer

Using the first law of thermodynamics: \mathrm{\Delta U=Q-W}

Given: Initial internal energy \mathrm{(U _{initial})}=2500 J Heat absorbed (Q) = 1200 J Work done (W) = 900 J

\mathrm{\Delta U=1200 \mathrm{~J}-900 \mathrm{~J}=300 \mathrm{~J}}

The change in internal energy is 300 J. Therefore, the final internal energy \mathrm{U_{final}}  is:

\mathrm{U_{\text {final }}=U_{\text {initial }}+\Delta U=2500 \mathrm{~J}+300 \mathrm{~J}=2800 \mathrm{~J}}

Therefore, the correct option is D.

Posted by

Irshad Anwar

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