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  • A gas undergoes an isobaric expansion at a temperature of , absorbing <img alt="500 \mat

A gas undergoes an isobaric expansion at a temperature of 400 \mathrm{~K}, absorbing 500 \mathrm{~J} of heat during this process. If the work done by the gas is 300 \mathrm{~J}, calculate the change in internal energy.

Option: 1

200 J


Option: 2

500 J


Option: 3

800 J


Option: 4

-200 J


Answers (1)

best_answer


According to the first law of thermodynamics, \mathrm{\Delta U=Q+W}, where \mathrm{\Delta U} is the change in internal energy, Q is the heat transfer, and W is the work done on the system. Since the process is isobaric, Substituting the values: \mathrm{Q=500 \mathrm{~J}, W=300 \mathrm{~J}}. Therefore, \mathrm{\Delta U=Q+W=500 \mathrm{~J}-300 \mathrm{~J}=200 \mathrm{~J}.}

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