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A geyser heats water flowing at a rate of \mathrm{2.0 \mathrm{~kg}} per minute from\mathrm{ 30^{\circ} \mathrm{C}\: to \: 70^{\circ} \mathrm{C}} . If geyser operates on a gas burner, the rate of combustion of fuel will be______\mathrm{ g\, min^{-1}}
[Heat of combustion \mathrm{ = 8\times 10^{3} Jg^{-1},}
Specific heat of water  \mathrm{ = 4.2\, Jg^{-1} }\: ^{0}\mathrm{C}^{-1}]

Option: 1

42


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Energy required for heating water in one minute \mathrm{\left(\Delta t=1\right. min)}
\mathrm{\frac{E}{\Delta t}= \frac{mc\Delta T}{\Delta t}}
         \mathrm{=\frac{2000 \times 4.2 \times 40}{1 \mathrm{~min}} }
\mathrm{\frac{E}{\Delta t}=336\times 10^{3}\left ( \frac{J}{min} \right ) }

Rate of combustion of fuel is let say R
\mathrm{\therefore R= \frac{\left ( E/\Delta t \right )}{\text{Heat of combustion}} }
          \mathrm{= \frac{336\times 10^{3}\: J/min}{8\times 10^{3}\, Jg^{-1}} }
\mathrm{R= 42\left ( \frac{g}{min} \right ) }

 

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