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A hydraulic structure has four gates which operate independently. The probability of failure of each gate is 0.2 . Given that gate 1 has failed, the probability that both gates 2 and 3 will fail is

Option: 1

0.240


Option: 2

0.200


Option: 3

0.040


Option: 4

0.008


Answers (1)

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The required probability = (Prob. of failure of gate 2) X (Prob. of failure of gate 3)

{independent events}

                    \begin{aligned} & =(0.2)(0.2) \\ \\& =0.040 \end{aligned}

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Anam Khan

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