Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A hydrogen atom in its ground state absorbs of energy. The angular momentum of electron of

A hydrogen atom in its ground state absorbs \mathrm{10.2eV} of energy. The angular momentum of electron of the hydrogen atom will increase by the value of :

( Given, Planck's constant \mathrm{=6.6\times10^{-34}Js} ).

Option: 1

\mathrm{2.10\times 10^{-34}Js}


Option: 2

\mathrm{1.05\times 10^{-34}Js}


Option: 3

\mathrm{3.15\times 10^{-34}Js}


Option: 4

\mathrm{4.2\times 10^{-34}Js}


Answers (1)

best_answer

\mathrm{E_{f}=E_{i}+\Delta E} \\

\mathrm{-\frac{13.6}{n_{f}^{2}}=\frac{-13.6}{1^{2}}+10.2 \mathrm{eV}} \\

\mathrm{n_{f}^{2}=\frac{-13.6}{-3.4}=4} \\

\mathrm{n_{f}=2}

\mathrm{\therefore } The electron will jump from the ground state to the first excited state orbit.

According to Bohr's model

\mathrm{L=\frac{n h}{2 \pi}, \qquad L \rightarrow\: angular\: momentum}\\

\mathrm{L_{i}=\frac{h}{2 \pi}, \quad L_{f}=\frac{2 h}{2 \pi}=\frac{h}{\pi}}\\

\mathrm{\Delta L=L_{f}-L_{i}=\frac{h}{2 \pi}=\frac{6.6 \times 10^{-34}}{2 \times 3.14}}\\

\mathrm{\Delta L=1.05 \times 10^{-34} \mathrm{~J}-\mathrm{s}}

Hence the correct answer is option 2.

Posted by

qnaprep

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads
anam-khan

Bihar Board extends BSEB Super 50 free coaching application last date to March 26
anam-khan

JEE Main City Intimation Slip 2025 Live: NTA session 2 exam city slips soon at jeemain.nta.nic.in

Latest Question