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A is a point on either of two lines y+\sqrt{3}|\mathrm{x}|=2 at a distance of \frac{4}{\sqrt{3}} units from their point of intersection. The co-ordinates of the foot of perpendicular from A on the bisector of the angle between them are

Option: 1

\left(-\frac{2}{\sqrt{3}}, 2\right)


Option: 2

(0,0)


Option: 3

\left(\frac{2}{\sqrt{3}}, 2\right)


Option: 4

\left ( 0,4 \right )


Answers (1)

best_answer

Draw figure


\mathrm{y+\sqrt{3} x=2 \quad \text { for } x>0}
\mathrm{ y=-\sqrt{3} x=2 \quad \text { for } x<0 \quad}

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Ritika Kankaria

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