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A loaded dice has following probability distribution of occurrences

Dice Value 1 2 3 4 5 6
Probability \frac{1}{4} \frac{1}{8} \frac{1}{8} \frac{1}{8} \frac{1}{8} \frac{1}{4}

If three identical dice as the above are thrown, the probability of occurrence of values 1,5 and 6 on the three dice is

Option: 1

Same as that of occurrence of 3,4,5


Option: 2

Same as that of occurrence of 1,2 ,5


Option: 3

\frac{1}{128}


Option: 4

\frac{5}{8}


Answers (1)

best_answer

Probability of occurrence of 1,5 and 6

         \mathrm{P(1,5,6)=\frac{1}{4} \times \frac{1}{8} \times \frac{1}{4}=\frac{1}{128}}

                                              [\because Dices are independent]

Probability of occurrence of 3,4 and 5

         \mathrm{P(3,4,5)=\frac{1}{8} \times \frac{1}{8} \times \frac{1}{8}=\frac{1}{512}}

Probability of occurrence of 1,2 and 5

         \mathrm{P(1,2,5)=\frac{1}{4} \times \frac{1}{8} \times \frac{1}{8}=\frac{1}{256}}

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Ritika Harsh

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