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A man weighs 80 Kg. He stands on a weighing machine in a lift which is going downwards with a uniform acceleration of 5 m/s2 . What would be the reading of the machine? (reading in Newtons) 

 

Option: 1

400


Option: 2

1200


Option: 3

800


Option: 4

100


Answers (1)

best_answer

 

As we have learned

When Lift accelerating down with 'a'  (a<g)

 So  mg-R=ma

R=m(g-a)

i.e  Apparent weight  <  Actual weight

Draw FBD of man 

               R

mg-R = 5m 

 R = m ( g-5 )

R = 80 * 5 

R = 400 N 

Posted by

Sayak

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