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A mass m is attached to two strings as shown in figure. The spring constants of two springs are K1 and K2. For
the frictionless surface, the time period of oscillation of mass m is

 

 

Option: 1

2 \pi \sqrt{\frac{m}{K_1-K_2}}


Option: 2

\frac{1}{2 \pi} \sqrt{\frac{K_1-K_2}{m}}


Option: 3

\frac{1}{2 \pi} \sqrt{\frac{K_1+K_2}{m}}


Option: 4

2 \pi \sqrt{\frac{m}{K_1+K_2}}


Answers (1)

best_answer

Both the springs are in parallel.
\begin{aligned} & K_{e q}=K_1+K_2 \\ & T=2 \pi \sqrt{\frac{m}{K_{e q}}}=2 \pi \sqrt{\frac{m}{K_1+K_2}} \end{aligned}

Posted by

vishal kumar

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