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A metal block of base area 0.20 \mathrm{~m}^2 is placed on a table, as shown in figure. A liquid film of thickness 0.25 \mathrm{~mm} is inserted between the block and the table. The block is pushed by a horizontal force of 0.1 \mathrm{~N} and moves with a constant speed. If the viscosity of the liquid is 5.0 \times 10^{-3} \mathrm{Pl} , the speed of block is  ____________ \times 10^{-3} \mathrm{~m} / \mathrm{s}.

 

Option: 1

25


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & |F|=\eta A \frac{\Delta v}{\Delta h} \\ & 0.1=5 \times 10^{-3} \times 0.2 \times \frac{v}{0.25 \times 10^{-3}} \\ & v=0.025 \mathrm{~ms}^{-1} \\ & v=25 \times 10^{-3} \mathrm{~ms}^{-1} \end{aligned}

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Ritika Jonwal

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