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  • A metal block of mass m is suspended from a rigid support through a metal wire of diameter 14 mm. The tensile stress developed in the wire under equilibrium state is <img alt="7\times 1

A metal block of mass m is suspended from a rigid support through a metal wire of diameter 14 mm. The tensile
stress developed in the wire under equilibrium state is 7\times 10^{5} Nm^{-2} . The value of mass m is _____kg.

(Take, g=9.8ms^{-2}   and  \pi=\frac{22}{7} )

Option: 1

11


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\text { Using stress }=\frac{\text { force }}{\text { area }}=\frac{\mathrm{mg}}{\mathrm{A}}

\Rightarrow \mathrm{m}=\frac{\mathrm{S} \times \mathrm{A}}{\mathrm{g}}=\frac{7 \times 10^5 \times \pi \mathrm{R}^2}{\mathrm{~g}}

\begin{aligned} & =\frac{7 \times 10^5 \times \frac{22}{7} \times\left(7 \times 10^{-3}\right)^2}{9.8} \\ & =11 \mathrm{~kg} \end{aligned} (Note: 14 mm is diameter)

Posted by

Irshad Anwar

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