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  • A meter bridge is set up as shown, to determine an unknown resistance ‘X’ using a standard 10 ohm resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-

A meter bridge is set up as shown, to determine an unknown resistance ‘X’ using a standard 10 ohm resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of ‘X’ is

Option: 1

10.2 ohm


Option: 2

10.6 ohm


Option: 3

10.8 ohm


Option: 4

11.1 ohm


Answers (1)

At Null point 

\frac{\mathrm{X}}{l_1}=\frac{10}{l_2}

Here, l_1=52+\text { End correction }=52+1=53 \mathrm{~cm}

          l_2=48+\text { End correction }=48+2=50 \mathrm{~cm}

\mathrm{\therefore \quad \frac{X}{53}=\frac{10}{50}}                           \mathrm{\therefore \quad X=\frac{53}{5}=10.6 \Omega}

Posted by

Sumit Saini

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