Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A Mixture of Helium and <img alt="7 \mathrm{~gm}" src="https://entrancecorner.oncodecogs.

A Mixture of 4 \mathrm{~gm} Helium and 7 \mathrm{~gm} Nitrogen is enclosed in a vessels of constant volume at 300 \mathrm{~K}.
The quantity of Meat absorbed by the Mixture to double the Root mean velocity ot ito Molecule [ R= universal mas (content)]
 

Option: 1

2725 \mathrm{~R}


Option: 2

3825\mathrm{~R}


Option: 3

3630\mathrm{~(R)}


Option: 4

1912.5 \mathrm{(R)}


Answers (1)

best_answer

\begin{aligned} &\mathrm{Q=\Delta v+\omega}\\ &\mathrm{\omega=\text{0 since volume is constant}}\\ &\mathrm{Q=\Delta U}\\ &\mathrm{ \text { Vrms }=\sqrt{3 R T} / M }\\ &\mathrm{ U_{\text {mis }}=U_1+U_2}\\ &\mathrm{ \text { UMix }=n_1 c_{v_1} T+n_2\left(v_2 T\right. }\\ &\mathrm{ =\left(n_1+n_2\right)\left((v)_{\text {mis }} T\right. }\\ &\mathrm{ (\cup f)-\left(v_i\right)=n\left(v\left(T_2-T,\right)=\left(n_1+n_2\right)\left(( V ) _ { \text { Min } } \left(T_2-T_4\right.\right.\right. }\\ &\mathrm{ v_{\text {rms }}^{\prime}=2 v_{\text {ams }} \Rightarrow T^{\prime}=4 T }\\ &\mathrm{ n_1=\frac{4}{4}=1 \quad n_2=\frac{7}{28}=\frac{1}{4}} \end{aligned}

\begin{aligned} &\mathrm{ (v)_{\text {mix }}=\frac{n_1 c v_1+n_2 c_2}{n_1+n_2} }\\ &\mathrm{ u_f-v_i=l_1\left(v_1+n_2\left(v_2\right)\left(T_2-T_r\right)\right. }\\ &\mathrm{ =2 \times 3 }\\ &\mathrm{ =\left[1 \times \frac{3}{2}+\frac{1}{4} \times \frac{5}{2}\right] R[1200-300] }\\ &\mathrm{ =\left[\frac{3}{2}+\frac{5}{8}\right] \times R \times 900 }\\ &\mathrm{ =1912.5 R }\\ \end{aligned}

Posted by

Sayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus
anam-khan

JEE Main 2026 correction window opens tomorrow; NTA allows exam city change

Latest Question