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A monkey of mass \mathrm{50 \mathrm{~kg}} climbs on a rope which can withstand the tension \mathrm{(T) } of \mathrm{350 \mathrm{~N}. } If monkey initially climbs down with an acceleration of  \mathrm{4 \mathrm{~m} / \mathrm{s}^{2}} and then climbs up with an acceleration of \mathrm{ 5 \mathrm{~m} / \mathrm{s}^{2}.} Choose the correct option \mathrm{ \left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right).}

Option: 1

\mathrm{T}=700 \mathrm{~N} \text { while climbing upward }


Option: 2

\mathrm{T}=350 \mathrm{~N} \text { while going downward }


Option: 3

\text { Rope will break while climbing upward }


Option: 4

\text { Rope will break while going downward }


Answers (1)

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\mathrm{mg-T_{1}=ma_{1}}\rightarrow (1)

\mathrm{T_{2}-mg=ma_{2}}\rightarrow (2)

\mathrm{a_{1}=4m/s^{2}(given)}

\mathrm{500-T_{1}=50(4)}

\mathrm{T_{1}=300N}

In upwand motion, the tension will more than the downward motion

So, the maximum value of \mathrm{T_2} possible is \mathrm{350 \mathrm{~N}}

but,
\mathrm{a_2 =5 \mathrm{~m} / \mathrm{s}^2 }
\mathrm{T_2-500 =50 \times 5 }
\mathrm{T_2 =750 \mathrm{~N}}
\therefore The rope  will break while climbing upward

Hence (3) is correct option

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