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 A 16 \mathrm{~cm}^3 of water flows per second through a capillary tube of radius r \mathrm{~cm} and length l \mathrm{~cm}, when connected to a pressure head of \mathrm{h} \mathrm{~cm} of water. If a tube of the same length and radius \frac{r}{2}  is connected to the same pressure head. Find the mass of water flowing per minute through the tube-
 

Option: 1

40 \mathrm{~g} / \mathrm{min}


Option: 2

52 \mathrm{~g} / \mathrm{min}


Option: 3

60 \mathrm{~g} / \mathrm{min}


Option: 4

70 \mathrm{~g} / \mathrm{min}


Answers (1)

best_answer

Using, Q=\frac{\pi p r^4}{8 \eta s}

\begin{aligned} & \frac{Q^{\prime}}{Q_2}=\frac{\left(\frac{r}{2}\right)^4}{r^4} \\ Q^{\prime} & =\left(\frac{1}{16}\right) Q=\frac{1}{16} \times 16 \\ & Q^{\prime}=1 \mathrm{~cm}^3 / \mathrm{sec} \\ \therefore \text { Mass } & =\rho Q^{\prime} \\ & =1 \times 1=1 \mathrm{~g} / \mathrm{sec} \end{aligned}
The mass of the water flowing per minute
\begin{aligned} & =1 \times 60 \mathrm{~g} / \mathrm{sec} . \\ & =60 \mathrm{~g} / \mathrm{sec} \end{aligned}
 

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Gaurav

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