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IMG_20180809_174633_603.JPG A parachutist after bailing out falls 50 m without-friction. When parachute opens, it decelarares 2 m/s^2. He reaches the ground with a speed of 3 m/sec. At what height, did he bail (A) 91 m (C) 293 m (B) 182 m (D) 111 m rdation 01000flional to its displacement loss

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 IMG_20180809_174633_603.JPG IMG_20180809_174633_603.JPG

  Initially, the parachutist falls under gravity

u^{2}= 2ah= 2\times 9.8\times 50= 980 m^{-2}s^{-2}

He reaches the ground with speed

= 3m/s,a= -2ms^{-2}

\therefore \left ( 3 \right )^{2}= u^{2}-2\times 2\times h_{1}

or\: \: 9= 980-4h_{1}

or\: \: h_{1}=\frac{971}{4}

or\: \: h_{1}=242.75m

\therefore Total\: height\: = 50 + 242.75

= 292.75

= 293m

 

Posted by

Safeer PP

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