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  • A parallel plate capacitor filled with a medium of dielectric constant 10 , is connected across a battery and is charged. The dielectric slab is replaced by another slab of dielectric constant 15.

A parallel plate capacitor filled with a medium of dielectric constant 10 , is connected across a battery and is charged. The dielectric slab is replaced by another slab of dielectric constant 15. Then the energy of capacitor will :
 

Option: 1

Increase by 50%
 


Option: 2

 Decrease by 15 \%
 


Option: 3

Increase by 25 \%
 


Option: 4

Increase by 33 \%


Answers (1)

best_answer

\mathrm{U=\frac{1}{2}(kC_{\circ })V^{2}}

\mathrm{\frac{U^{\prime}}{U}=\frac{k^{\prime}}{k}=\frac{15}{10}=1.5}

\mathrm{\frac{\Delta U}{U} \times 100=\frac{U^{\prime}-U}{U} \times 100}

                       \mathrm{=(1.5-1)\times 100}

                        \mathrm{=50\%}

Hence, correct answer is Option (1).

Posted by

Kuldeep Maurya

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