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A parallel plate capacitor has circular plates, each of radius 5.0 \mathrm{~cm}. It is being charged so that electric field in the gap between its plates rises steadily at the rate of 10^{12} \mathrm{~V} / \mathrm{m}. What is the magnitude of displacement current?
 

Option: 1

0.04 \mathrm{~A}


 


Option: 2

0.05 \mathrm{~A}
 


Option: 3

0.06 \mathrm{~A}
 


Option: 4

0.07 \mathrm{~A}


Answers (1)

best_answer

\mathrm{I_D=\varepsilon_0 \frac{\mathrm{d} \phi_E}{\mathrm{dt}}=\varepsilon_0 \pi r^2 \frac{\mathrm{dE}}{\mathrm{dt}}=8.85 \times 10^{-12} \times \pi \times\left(5 \times 10^{-2}\right)^2 \times 10^{12}=0.07 \mathrm{~A} . }

Hence option 4 is correct.

Posted by

Riya

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