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A parallel plate capacitor has plate area 40 \mathrm{~cm}^2 and plates separation 2mm. The space between the plates is filled with a dielectric medium of a thickness 1 mm and dielectric constant 5. The capacitance of the system is:

Option: 1

24 \varepsilon_0 \mathrm{~F}


Option: 2

\frac{10}{3} \varepsilon_0 \mathrm{~F}


Option: 3

\frac{3}{10} \varepsilon_0 \mathrm{~F}


Option: 4

10 \varepsilon_0 \mathrm{~F}


Answers (1)

best_answer

\begin{aligned} & C_1=\frac{\varepsilon_0 \mathrm{~A}}{\mathrm{~d}}=\mathrm{C}_0 \\ & \mathrm{C}_2=\mathrm{K} \frac{\varepsilon_0 \mathrm{~A}}{\mathrm{~d}}=\mathrm{K} \varepsilon_0 \\ & \mathrm{Ceq}=\frac{\mathrm{C}_1 \mathrm{C}_2}{\mathrm{C}_1+\mathrm{C}_2}=\frac{\mathrm{C}_0 \times \mathrm{KC}_0}{(\mathrm{~K}+1) \varepsilon_0}=\frac{\mathrm{KC}_0}{\mathrm{~K}+1} \\ & =\frac{5 \times \varepsilon_0 \times 40 \times 10^{-4}}{1 \times 10^{-3} \times 6} \\ & =\frac{10}{3} \varepsilon_0 \mathrm{~F} \end{aligned}

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SANGALDEEP SINGH

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