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A parallel plate capacitor is charged to \mathrm{60 \mu \mathrm{C} }. Due to a radioactive source, the plate loss charge at the rate of \mathrm{1.8 \times 10^{-8} \mathrm{Cs}^{-1}. } The magnitude of displacement current is

Option: 1

1.8 \times 10^{-8} \mathrm{Cs}^{-1}


Option: 2

3.6 \times 10^{-8} \mathrm{Cs}^{-1}


Option: 3

4.1 \times 10^{-11} \mathrm{Cs}^{-1}


Option: 4

5.7 \times 10^{-12} \mathrm{Cs}^{-1}


Answers (1)

best_answer

Displacement current is given by
\mathrm{I_d=\frac{d q}{d t}=1.8 \times 10^{-8} \mathrm{Cs}^{-1} }

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shivangi.shekhar

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