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A parallel plate capacitor made to circular plates each of radius \mathrm{R=6 \mathrm{~cm}} has capacitance \mathrm{\mathrm{C}=100 \mathrm{pF}}. The capacitance is connected to a \mathrm{230 \mathrm{~V}} A.C. supply with an angular frequency of \mathrm{300 \mathrm{rad} / \mathrm{s}.} The r.m.s. value of conduction current will be:
 

Option: 1

5.7 \mu \mathrm{a}

 


Option: 2

\quad 6.3 \mu \mathrm{A}
 


Option: 3

\quad 9.6 \mu \mathrm{A}
 


Option: 4

\quad 6.9 \mu \mathrm{A}


Answers (1)

best_answer

\mathrm{I_{R M S} =\frac{E_{R M S}}{X_C}=\omega C E_{R M S} }

          \mathrm{ =300 \times 10^{-10} \times 230=6.9 \mu \mathrm{A}}

Hence option 4 is correct.

 

Posted by

Ritika Jonwal

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