Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A parallel plate capacitor of capacitance 2 F is charged to a potential V, The energy stored in the capacitor is E1. The capacitor is now connected to another uncharged identical capacitor in paral

A parallel plate capacitor of capacitance 2 F is charged to a potential V, The energy stored in the capacitor is E1. The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is E2. The ratio \mathrm{E_{2}/E_{1}} is :

Option: 1

2:3


Option: 2

1:2


Option: 3

1:4


Option: 4

2:1


Answers (1)

best_answer

\mathrm{C=2F}       

\mathrm{E1=\frac{1}{2}CV^{2}} ..............(1)

Now

 

\begin{aligned} & \mathrm{V}_{\mathrm{C}}=\frac{\mathrm{C}_1 \mathrm{~V}_1+\mathrm{C}_2 \mathrm{~V}_2}{\mathrm{C}_1+\mathrm{C}_2} \\ & \mathrm{~V}_{\mathrm{C}}=\frac{\mathrm{CV}+\mathrm{O}}{2 \mathrm{C}}=\frac{\mathrm{V}}{2} \\ & \mathrm{E}_2=\mathrm{CV^2_C}=\mathrm{C} \cdot \frac{\mathrm{V}^2}{4} \\ \end{aligned}.............(2)

\begin{aligned} & \frac{\mathrm{E}_2}{\mathrm{E}_1}=\frac{\left(\frac{\mathrm{CV}^2}{4}\right)}{\left(\frac{\mathrm{CV}^2}{2}\right)}=\frac{2}{1} \end{aligned}

Posted by

Info Expert 30

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: BTech CSE cut-offs for PwD candidates at NITs make entry easy; top institutes still selective
anam-khan

73 or 99 percentile? JEE Main result questioned, J-K candidate says, ‘Don’t create hype’
anam-khan

JEE Main 2025: 11 from Kota coaching centres among 24 students with 100 percentile

Latest Question