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  • A parallel plate capacitor with plate area  and separation between the plates <img alt="\math

A parallel plate capacitor with plate area \mathrm{ A} and separation between the plates \mathrm{d} is charged by a constant current \mathrm{ I}. Consider a plane surface of area \mathrm{ \frac{A}{3}} parallel to the plates and drawn symmetrically between the plates. The displacement current through this area is:
 

Option: 1

\mathrm{I}

 


Option: 2

\frac{\mathrm{I}}{3}
 


Option: 3

\frac{2 \mathrm{I}}{3}
 


Option: 4

\frac{\mathrm{I}}{6}


Answers (1)

best_answer

The displacement current = conduction current =\mathrm{I} corresponding to area \mathrm{A}. Therefore displacement current for area \mathrm{\frac{\mathrm{A}}{3}} is \mathrm{\frac{\mathrm{I}}{3}}.

Hence option 2 is correct.

Posted by

Rakesh

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