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  • A partical is moving with a constant speed of 8 m/s in circular path of radius 1 m. What will be the displacement  of particle in 1 sec.Option: 1</stro

A partical is moving with a constant speed of 8 m/s in circular path of radius 1 m. What will be the displacement  of particle in 1 sec.

Option: 1

2 sin 80


Option: 2

2 sin 40


Option: 3

4 sin 80


Option: 4

4 sin 40


Answers (1)

best_answer

As we learn

Displacement in Circular Motion -

\Delta r = 2r sin \frac{\theta}{2}

\Delta r = displacement 

\theta=Angle between two vectors

 

- wherein

If |\vec{r_{1}}|=|\vec{r_{2}}|=r

 

 Let the angular displacement of particle from A to B will be 

2R\sin \frac{\Theta }{2}

Length of circular arc AB =8*1 =8m

Angle \Theta =\frac{arc\: \: length}{Radius}=\frac{\Theta }{1}=8 rad

d =2R\sin \frac{\Theta }{2}=2*1*\sin \frac{8 }{2}

2\sin 4^{0}

 

Posted by

manish

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