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  • A particle executes simple harmonic motion. Its amplitude is and time period is <img alt=

A particle executes simple harmonic motion. Its amplitude is 8 \mathrm{~cm} and time period is 6 \mathrm{~s}. The time it will take to travel from its position of maximum displacement to  the point corresponding to half of its amplitude, is __________ \mathrm{~s} .

Option: 1

1


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer



Time taken from the extreme position to \mathrm{X= \frac{A}{2}} is  \mathrm{\frac{T}{6}}
\mathrm{t= \frac{T}{6}= \frac{6}{6}= 1\, second}

The correct answer is (1)

Posted by

Devendra Khairwa

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