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  • a particle is moving with velocity v=k[yi+xj] where k is constant the general equation for its path is

A particle is moving with velocity v=k[yi+xj], where k is constant. The general equation for its path is:

Answers (1)

\frac{\mathrm{d} x}{\mathrm{d} t} = ky ..... (1)

\frac{\mathrm{d} y}{\mathrm{d} t} = kx......(2)

divide eq 2 by 1

\frac{\mathrm{d} y}{\mathrm{d} x} = \frac{x}{y}

y\mathrm{d}y = x\mathrm{d}x

\int y\mathrm{d}y = \int x\mathrm{d}x

\Rightarrow y^{2} -x^{2}= c

 

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