Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • a particle is moving with velocity v=k[yi+xj] where k is constant the general equation for its path is

A particle is moving with velocity v=k[yi+xj], where k is constant. The general equation for its path is:

Answers (1)

\frac{\mathrm{d} x}{\mathrm{d} t} = ky ..... (1)

\frac{\mathrm{d} y}{\mathrm{d} t} = kx......(2)

divide eq 2 by 1

\frac{\mathrm{d} y}{\mathrm{d} x} = \frac{x}{y}

y\mathrm{d}y = x\mathrm{d}x

\int y\mathrm{d}y = \int x\mathrm{d}x

\Rightarrow y^{2} -x^{2}= c

 

Posted by

lovekush

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2026 Registration LIVE: NTA session 1 application dates soon; exam, registration fee updates
anam-khan

JEE Mains 2026 Registration LIVE: NTA JEE session 1 application, exam dates soon; city choice available
anam-khan

JEE Main 2026 exam city option not removed: NTA dismisses viral claim

Latest Question