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IMG_20190119_105443.jpg A particle is thrown upward from ground. it experiences a constant resistance force which can produce retardation 2m/s^2. the ratio of time of ascent to the time of descent is

Answers (1)

v = u + at
0 = u + -(g + 2)t
t = u / (g + 2)

0 - u^2 = 2as
- u^2 = 2 *-(g + 2)s
s = u^2 / 2(g + 2)

s = 1/2 aT^2
u^2 / 2(g+2) = (1/2) * (g-2)T^2
u / sqrt(g^2 - 4) = T

So t/T = sqrt (g-2) / sqrt (g+2)

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Safeer PP

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