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A particle of charge q and mass m is projected with a velocity v_0 towards a circular region having witorm magnetic field B perpendicular and into the plane of paper form point P as. R is the radius and O is the centre, The value of v_0 so that particle passes through O is -

Option: 1

\frac{q B R}{m \sin \theta}


Option: 2

\frac{qBR}{2m \sin \theta}


Option: 3

\frac{2 q B R}{m \sin \theta}


Option: 4

\frac{3 q B R}{2 m \sin \theta}


Answers (1)

best_answer

If the particle pase es through O, the situation can be shown. Let r the radius of circular path then from the given.

\sin \theta=\frac{R / 2}{r}=\frac{R}{2 r} \Rightarrow r_0=\frac{m v}{q B}

\sin \theta=\frac{Rq B}{2 m v}

v_0=\frac{qBR}{2m \sin \theta}

Posted by

Devendra Khairwa

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