Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A partition wall has two layers A and B in contact with each other. They have the same thickness but the thermal conductivity of layer A is twice that the temperature difference across the layer B

A partition wall has two layers A and B in contact with each other. They have the same thickness but the thermal conductivity of layer A is twice that the temperature difference across the layer B is 50K, then the corresponding difference across layer A is

Option: 1

50K


Option: 2

12.5K


Option: 3

25K


Option: 4

60K


Answers (1)

best_answer

As we have learnt,

@2729

\frac{\Delta T_1}{R_1} = \frac{\Delta T_2}{R_2}

\Delta T_1 = \Delta T_2\left(\frac{R_1}{R_2} \right )

\Delta T_1 = \Delta T_2\cdot \left(\frac{K_2}{K_1} \right )

\Delta T_1 = 50K\times \left(\frac{1}{2} \right ) = 25 K

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question