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  • A pendulum bob of mass  and carrying a charge <img alt="2\times 10^{-8}C"

A pendulum bob of mass 30.7\times 10^{-6}kg and carrying a charge 2\times 10^{-8}C is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is ( g = 10 m/s2)

Option: 1

3\times 10^{-4} N


Option: 2

4\times 10^{-4} N


Option: 3

5 \times 10^{-4} N


Option: 4

6 \times 10^{-4} N


Answers (1)

best_answer

 \\T = \sqrt{(mg^2) + (QE)^2} = \sqrt{(30.7\times10^{-6}\times 9.8)^2 + (2\times 10^{-8}\times 20000)^2} \\ T= 5\times 10^{-4} N

 

Posted by

chirag

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