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A person A is moving along east and B is moving along north. Then relative velocity of A with respect to B is (V_{A}=10\, m/s\, ,\; V_{B}=10\sqrt{3}\, m/s)

Option: 1

20 m/s along north


Option: 2

 20 m/s along south 


Option: 3

20 m/s along 1200 with east

 


Option: 4

None of the above


Answers (1)

best_answer

\underset{V_A}{\rightarrow} = Velocity of object A.

\underset{V_B}{\rightarrow} = Velocity of object B.

The relative velocity  of B wrt to A is \underset{V_{B/A}}{\rightarrow}

 

\underset{V_{B/A}}{\rightarrow}  =  \underset{V_{B}}{\rightarrow}  - \underset{V_{A}}{\rightarrow}  =10\sqrt{3}\; \hat{j}-10\, \hat{l}

\left | \underset{V_{B/A}}{\rightarrow} \right |   =  \sqrt{100+300}=20\, m/s

\tan \theta =\frac{V_{B}}{V_{A}}=\frac{10\sqrt{3}}{10}=\sqrt{3}

So \theta =60^0 \ \ from \ \ west

i.e \theta =120^{\circ}\; \; from\; \; east

 

Posted by

Ajit Kumar Dubey

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