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  • A person on a trip has a choice between private car and public transport. The probability of using a private car is 0.45 . While using the public transport further choices available are bus and met

A person on a trip has a choice between private car and public transport. The probability of using a private car is 0.45 . While using the public transport further choices available are bus and metro, out of which the probability of commuting by a bus is 0.55 . In such a situation, the probability (rounded up to two decimals) of using a car, bus and metro, respectively would be

 

Option: 1

0.45,0.30 and 0.25
 


Option: 2

0.45,0.25 and 0.30


Option: 3

0.45,0.55 and 0.00


Option: 4

0.45,0.35 and 0.20


Answers (1)

best_answer

Obviously, probability of using a car

                   = 0.45

Probability of using a bus = Probability of using publictransport x Prob. of commuting by a bus

                    \begin{aligned} & =(1-0.45) \times(0.55) \\ & =0.3025 \\ & =0.30 \end{aligned}

Probability of using a metro = (Prob. of using public transport ) x (Prob. of commuting by metro)

                    \begin{aligned} & =(1-0.45)(1-0.55) \\ & =0.2475 \\ & =0.25 \end{aligned}

                

Posted by

jitender.kumar

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