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  • A point charge  is placed outside a hollow conductor of radius <img alt="\mathrm{r}" src="https:

A point charge \mathrm{Q}  is placed outside a hollow conductor of radius \mathrm{r}, at a distance \mathrm{r(r>R)} from its centre \mathrm{C}. The electric field at the centre \mathrm{C} of the conductor due to charges induced on it.

Option: 1

\mathrm{prop \, to \: r^{2}}


Option: 2

\mathrm{prop \, to \: r}


Option: 3

\mathrm{prop \, to \: r^{-2}}


Option: 4

\mathrm{prop \, to \: r^{3}}


Answers (1)

best_answer

If \vec{E}_{1}  is the electric field of charge Q at C and \vec{E}_{2} due to induced charge, then

\vec{E}_{1}+\vec{E}_{2}=0

\vec{E}_{2}=-\vec{E}_{1} \text { or } E_{2}=E_{1}

=\frac{1}{4 \pi \epsilon _{0}} \frac{Q}{r^{2}}  Ans.

Posted by

Shailly goel

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