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  • A point charge q1 = 4q0 is placed at origin.Another point charge q2 = −q0 is placed at = 12 cm. Charge of proton is q0. The proton

A point charge q1 = 4q0 is placed at origin.Another point charge q2 = −q0 is placed at = 12 cm. Charge of proton is q0. The proton is placed on x axis so that the electrostatic force on the proton is zero.In this situation,the position of the proton from the origin is ___________ cm.

Option: 1

24


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

q_1=4q_o and q_2=-q_o

Electric field at point A will be zero.

\begin{aligned} & \left|\overrightarrow{\mathrm{E}_1}\right|=\left|\overrightarrow{\mathrm{E}_2}\right| \\ & \frac{k q_1 \cdot q_0}{(12+x)^2}=\frac{k q_2 \cdot q_0}{x^2} \\ & \frac{4 q_0}{(12+x)^2}=\frac{q_0}{x^2} \\ & 4 x^2=(12+x)^2 \\ & \pm 2 \mathrm{x}=(12+\mathrm{x}) \\ & 2 x=12+x \\ & -2 x=12+x \\ & x=12 \\ & -3 x=12 \\ & x=12 \mathrm{~cm} \\ & x=x=-\frac{12}{3}=-4 \\ & \end{aligned}

Position of proton from origin will be → 12+12

                                                          → 24 cm

Posted by

Ajit Kumar Dubey

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