Get Answers to all your Questions

header-bg qa

A polarizer-analyzer set is adjusted such that the intensity of light coming out of the analyzer is just 10% of the original intensity. Assuming that the polarizer-analyzer set does not absorb any light, the angle by which the analyzer needs to be rotated further to reduce the output intensity to be zero is:  
Option: 1 71.6o
Option: 2 90o
Option: 3 18.4o  
Option: 4 45o
 

Answers (1)

best_answer

 

 

Malus's Law -

Malus's Law-

This law states that the intensity of the polarized light transmitted through the analyzer varies as the square of the cosine of the angle between the plane of transmission of the analyzer and the plane of the polarizer.

                                       

As, 

                                                    I=I_{0} \cos ^{2} \theta

 

output intensity is given by I=I_0Cos^2(\theta )

Initial output intensity=10% of I_0

I.e \frac{10I_0}{100}=I_0Cos^2(\theta )\Rightarrow \theta =71.57

Final output intensity=O

means new angle is 90^0

the angle by which the analyser needs to be rotated further is 90^0-\theta =18.4^0

 

So Option (3) is correct.

Posted by

Ritika Jonwal

View full answer