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  • A potentiometer experiment is conducted to determine the internal resis- tance of a cell. A standard cell of known EMF 1.2V is connected to the potentiometer. The null point is obtained at a length

A potentiometer experiment is conducted to determine the internal resis- tance of a cell. A standard cell of known EMF 1.2V is connected to the potentiometer. The null point is obtained at a length of 60 cm. When the cell being tested is connected instead of the standard cell, the null point is obtained at a length of 45 cm. Calculate the internal resistance of the cell being tested.

Option: 1

4.8 Ω


Option: 2

79.5 Ω


Option: 3

59.5 Ω


Option: 4

3.0 Ω


Answers (1)

best_answer

The internal resistance (r) of a cell can be determined using the formula:
r = Length of Potentiometer Wire × Known EMF/ Change in Potentiometer Length

Substitute the given values:
Length of Potentiometer Wire = 60 cm
Known EMF = 1.2 V

Change in Potentiometer Length = 60 cm − 45 cm = 15 cm
Calculate the internal resistance:
r=\frac{60}{15} = 4.8\Omega

Hence, the internal resistance of the cell being tested is 4.8 Ω.

Posted by

shivangi.bhatnagar

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