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A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface is

Option: 1

E/c


Option: 2

2E/c


Option: 3

Ec


Option: 4

E/c^{2}


Answers (1)

best_answer

As we discussed in

For EM wave

E=pc or p=\frac{E}{c}

Since after Reflection change in momentum is 2p=\frac{2E}{c}

Posted by

Sanket Gandhi

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