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A radioactive element  ^{242}_{92}X emits two \alpha–articles, one electron and two positrons. The product nucleus is represented by ^{234}_{P}Y. The value of P is

Option: 1

87


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

{ }_{92} \mathrm{X}^{242} \longrightarrow{ }_{\mathrm{p}} \mathrm{Y}^{234}+2_2 \alpha^4+_{-1} \mathrm{e}^0+2_{+1} \mathrm{e}^0

Using charge conservation:
92 = P + 2(2) + (-1) + 2(1)
92 = P + 5
P =87 
 

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Divya Prakash Singh

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