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A radioactive nucleus emits 3 \alpha -particles and 5 \beta -particles. The ratio of number of neutrons to that of protons will be:

Option: 1

\frac{A-Z-12}{Z-6}


Option: 2

\frac{A-Z}{Z-1}


Option: 3

\frac{A-Z-11}{Z-6}


Option: 4

\frac{\mathrm{A}-\mathrm{Z}-11}{\mathrm{Z}-1}


Answers (1)

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During the emission of \alpha -particle, the mass number and atomic number decreases by four and two respectively. During the emission of \beta -particle the mass number remains the same while the atomic number increases by 1.

{ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X} \stackrel{3 \alpha}{\longrightarrow}{ }_{(\mathrm{Z}-6)}^{(\mathrm{A}-12)} \mathrm{Y} \stackrel{5 \beta}{\longrightarrow}{ }_{(\mathrm{Z}-1)}^{(\mathrm{A}-12)} \mathrm{Y}^{\prime}

\therefore \frac{\text { No. of neutrons }}{\text { No.of protons }}=\frac{A-12-(Z-1)}{Z-1}=\frac{A-Z-11}{Z-1}

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Gunjita

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