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A ray of laser of a wavelength 630 \mathrm{~nm} is incident at an angle of 30^{\circ} at the diamond-air interface. It is going from diamond to air. The refractive index of diamond is 2.42 and that of air is 1 . Choose the correct option.
 
Option: 1 Angle of refraction is 24.41^{\circ}
 
Option: 2 Angle of refraction is 30^{\circ}
 
Option: 3 Refraction is not possible
 
Option: 4 Angle of refraction is 53.4^{\circ}

Answers (1)

best_answer

\lambda = 630 \, nm
              
\mu _{1}\sin i= \mu _{2}\sin r
2\cdot 42\times \sin 30^{\circ}= 1\times \sin r
\sin r= 1\cdot 21
\because \sin \theta \leq 1
\therefore Refraction is not possible
The correct option is (3)

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vishal kumar

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