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A rectangular block of mass 5 kg attached to a horizontal spiral spring executes simple harmonic motion of amplitude 1 m and time period 3.14 s. The maximum force exerted by spring on block is __________N.

Option: 1

20


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

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When an object executes S.H.M, its morning acceleration is given by a_{\text {max }}=\omega^2 \mathrm{~A}

Where \omega=\frac{2 \pi}{T}

Therefore, \mathrm{a}_{\max }=\frac{4 \pi^2 \mathrm{~A}}{\mathrm{~T}^2}

\begin{aligned} & F_{\max }=\operatorname{ma}_{\max }=5 \times \frac{4 \times 3.14 \times 3.14}{3.14 \times 3.14} \times(1) \\ & =20 \mathrm{~N} \end{aligned}

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Rishabh

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