Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A rectangular loop of length l and breadth b is placed at distance of x from infinitely long wire carrying current i such that the direction of current is parallel to breadth. If the loop moves awa

A rectangular loop of length l and breadth b is placed at distance of x from infinitely long wire carrying current i such that the direction of current is parallel to breadth. If the loop moves away from the current wire in a direction perpendicular to it with a velocity v, then magnitude of the emf in the loop is (\mu _{0}= =permeability of free space)

Option: 1

\mathrm{\frac{\mu_0 \mathrm{iv}}{2 \pi \mathrm{x}}\left(\frac{l+\mathrm{b}}{\mathrm{b}}\right)}


Option: 2

\mathrm{\frac{\mu_0 i^2 \mathrm{v}}{2 \pi^2 \mathrm{x}} \log \left(\frac{\mathrm{b}}{l}\right)}


Option: 3

\mathrm{\frac{\mu_0 \mathrm{i} l \mathrm{bv}}{2 \pi \mathrm{x}(l+\mathrm{x})}}


Option: 4

\mathrm{\frac{\mu_0 \mathrm{ilbv}}{2 \pi} \log \left(\frac{\mathrm{x}+l}{\mathrm{x}}\right)}


Answers (1)

best_answer

We can show the situation as

Since, loop is moving away from the wire, so the direction of current in the loop will be as shown in the figure.
Net magnetic field on the loop due to wire,\mathrm{B}=\frac{\mu_0 \mathrm{i}}{2 \pi}\left(\frac{1}{\mathrm{x}}-\frac{1}{l+\mathrm{x}}\right)=\frac{\mu_0 \mathrm{i} l}{2 \pi \mathrm{x}(l+\mathrm{x})}

So, the magnitude of the emf in the loop , \mathrm{e=v B b=\frac{\mu_0 i l v b}{2 \pi x(l+x)}}

Posted by

Riya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Amrita BTech Admission 2025: JEE Main-based registration deadline extended to August 30
anam-khan

DASA, CSAB Special round 2 seat allotment result 2025 declared on csab.nic.in

Latest Question