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  • A rectangular loop of sides 6 cm and 2 cm with a small cut is moving out of a region of uniform magnetic field of magnitude 0.4 T directed normal to the loop. The voltage developed across the cut i

A rectangular loop of sides 6 cm and 2 cm with a small cut is moving out of a region of uniform magnetic field of magnitude 0.4 T directed normal to the loop. The voltage developed across the cut if velocity of loop is \mathrm{\2cm^{-1}} in a direction normal to the longer side is:

Option: 1

\mathrm{3.8 \times 10^{-4} \mathrm{~V}


Option: 2

\mathrm{4.8 \times 10^{-4} \mathrm{~V}}


Option: 3

\mathrm{2.2 \times 10^{-2} \mathrm{~V}}


Option: 4

\mathrm{3.2 \times 10^{-2} \mathrm{~V}}


Answers (1)

best_answer

\mathrm{\text { Here, } l=6 \mathrm{~cm}=6 \times 10^{-2} \mathrm{~m}, \mathrm{~B}=0.4 \mathrm{~T}, \mathrm{v}=2 \mathrm{cms}^{-1}=2 \times 10^{-2} \mathrm{~ms}^{-1}}

\mathrm{\text { Voltage developed is } \varepsilon=\mathrm{Blv}=0.4 \times 6 \times 10^{-2} \times 2 \times 10^{-2}=4.8 \times 10^{-4} \mathrm{~V}}

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avinash.dongre

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